```
/**
*
* Ashish Patel
* e: ashishsushilPatel@gmail.com
* w: https://ashish.me
*
*/
/*
* Given an unsorted array of integers, find the length of longest increasing subsequence.
*
* Example:
*
* Input: [10,9,2,5,3,7,101,18]
* Output: 4
* Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
* Note:
*
* There may be more than one LIS combination, it is only necessary for you to return the length.
* Your algorithm should run in O(n2) complexity.
*/
function longestIncreasingSubsequence(nums) {
let dp = new Array(nums.length).fill(1)
let max = 0
for (let i = 1; i < nums.length; i++){
for (let j = 0; j < i; j++) {
if(nums[j] < nums[i]){
dp[i] = Math.max(dp[j] + 1, dp[i])
}
}
max = Math.max(max, dp[i])
}
return max
}
test('longest Increasing Subsequence', () => {
expect(longestIncreasingSubsequence([1,4,0,7])).toEqual(3)
expect(longestIncreasingSubsequence([10,9,2,5,3,7,101,18])).toEqual(4)
});
```

Created 2020-03-26T09:29:40+00:00 · Edit