### 1365 How Many Numbers Are Smaller Than The Current Number

```/**
*
* Ashish Patel
* e: ashishsushilPatel@gmail.com
* w: https://ashish.me
*
*/

/*
* Given the array nums, for each nums[i] find out how many numbers
* in the array are smaller than it. That is, for each nums[i] you
* have to count the number of valid j's such that j != i and nums[j]
* < nums[i].
*
* Example 1:
* Input: nums = [8,1,2,2,3]
* Output: [4,0,1,1,3]
* Explanation:
* For nums=8 there exist four smaller numbers than it (1, 2, 2 and 3).
* For nums=1 does not exist any smaller number than it.
* For nums=2 there exist one smaller number than it (1).
* For nums=2 there exist one smaller number than it (1).
* For nums=3 there exist three smaller numbers than it (1, 2 and 2).
*/

function howManyNumbersAreSmallerThanTheCurrentNumber(value) {
let result = new Array(value.length).fill(0)
for (let i = 0; i < value.length; i++) {
for (let j = 0; j < value.length; j++) {
if(value[i] !== value[j] && value[j] < value[i]){
result[i] += 1
}
}
}
return result
}

test('how Many Numbers Are Smaller Than The Current Number', () => {
expect(howManyNumbersAreSmallerThanTheCurrentNumber([8,1,2,2,3])).toEqual([4,0,1,1,3])
});```

Created 2020-04-20T13:03:10+00:00 · Edit