```
/**
*
* Ashish Patel
* e: ashishsushilPatel@gmail.com
* w: https://ashish.me
*
*/
/*
* We distribute some number of candies, to a row of n = num_people
* people in the following way:
*
* We then give 1 candy to the first person, 2 candies to the second
* We distribute some number of candies, to a row of n = num_people
* people in the following way:
*
* We then give 1 candy to the first person, 2 candies to the second
* person, and so on until we give n candies to the last person. Then,
* we go back to the start of the row, giving n + 1 candies to the
* first person, n + 2 candies to the second person, and so on until
* we give 2 * n candies to the last person.
*
* This process repeats (with us giving one more candy each time, and
* moving to the start of the row after we reach the end) until we run
* out of candies. The last person will receive all of our remaining
* candies (not necessarily one more than the previous gift).
*
* Return an array (of length num_people and sum candies) that represents
* the final distribution of candies.
*
* Example 1:
*
* Input: candies = 7, num_people = 4
* Output: [1,2,3,1]
* Explanation:
* On the first turn, ans[0] += 1, and the array is [1,0,0,0]
* On the second turn, ans[1] += 2, and the array is [1,2,0,0]
* On the third turn, ans[2] += 3, and the array is [1,2,3,0]
* On the fourth turn, ans[3] += 1 (because there is only one
* candy left), and the final array is [1,2,3,1]
*/
function distributeCandiesToPeople(candies, people) {
let result = new Array(people).fill(0)
let amount = 1
let index = 0
while(candies - amount > 0){
candies -= amount
result[index++ % people] += amount++
}
result[index++ % people] += candies
return result
}
test('distribute Candies To People', () => {
expect(distributeCandiesToPeople(60, 4)).toEqual([15,18,15,12])
expect(distributeCandiesToPeople(10, 3)).toEqual([5, 2, 3])
expect(distributeCandiesToPeople(7, 4)).toEqual([1, 2, 3, 1])
})
```

Created 2020-04-25T01:06:06+00:00 · Edit