### 1029 Two City Scheduling

```/**
*
* Ashish Patel
* e: ashishsushilPatel@gmail.com
* w: https://ashish.me
*
*/

/*
* There are 2N people a company is planning to interview. The cost of flying
* the i-th person to city A is costs[i], and the cost of flying the i-th
* person to city B is costs[i].
*
* Return the minimum cost to fly every person to a city such that exactly N
* people arrive in each city.
*
* Example 1:
*
* Input: [[10,20],[30,200],[400,50],[30,20]]
* Output: 110
* Explanation:
* The first person goes to city A for a cost of 10.
* The second person goes to city A for a cost of 30.
* The third person goes to city B for a cost of 50.
* The fourth person goes to city B for a cost of 20.
*
* The total minimum cost is 10 + 30 + 50 + 20 = 110 to have half the people interviewing in each city.
*/

function twoCityScheduling(costs) {
costs = costs.sort((a, b) => (a - a) - (b - b))
let totalCost = 0
let n = costs.length / 2
for (let i = 0; i < n; i++) {
totalCost += costs[i] + costs[i+n]
}
}

test('two City Scheduling', () => {
expect(
twoCityScheduling([
[10, 20],
[30, 200],
[400, 50],
[30, 20],
]),
).toEqual(110)
expect(
twoCityScheduling([
[259, 770],
[448, 54],
[926, 667],
[184, 139],
[840, 118],
[577, 469],
]),
).toEqual(1859)
})```

Created 2020-04-23T22:26:14+00:00 · Edit